1/2(x+6)=x+1/3(2x-5)

Solution for 1/2(x+6)=x+1/3(2x-5) equation:

1/2(x+6)=x+1/3(2x-5)

We move all terms to the left:

1/2(x+6)-(x+1/3(2x-5))=0


Domain of the equation: 2(x+6)!=0

x∈R



Domain of the equation: 3(2x-5))!=0

x∈R


We calculate fractions


(3x2/(2(x+6)*3(2x-5)))+(-(x+2xx)/(2(x+6)*3(2x-5)))=0


We calculate terms in parentheses: +(3x2/(2(x+6)*3(2x-5))), so:

3x2/(2(x+6)*3(2x-5))

We multiply all the terms by the denominator


3x2

We add all the numbers together, and all the variables

3x^2

Back to the equation:

+(3x^2)



We calculate terms in parentheses: +(-(x+2xx)/(2(x+6)*3(2x-5))), so:

-(x+2xx)/(2(x+6)*3(2x-5))

We add all the numbers together, and all the variables

-(+x+2xx)/(2(x+6)*3(2x-5))

We multiply all the terms by the denominator


-(+x+2xx)

We get rid of parentheses

-x-2xx

We add all the numbers together, and all the variables

-1x-2xx

Back to the equation:

+(-1x-2xx)


We get rid of parentheses

3x^2-1x-2xx=0