1/2(x+2)=2/5(5x-20)

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Solution for 1/2(x+2)=2/5(5x-20) equation: 



1/2(x+2)=2/5(5x-20)

We move all terms to the left:

1/2(x+2)-(2/5(5x-20))=0



Domain of the equation: 2(x+2)!=0

x∈R





Domain of the equation: 5(5x-20))!=0

x∈R



We calculate fractions


(5x5/(2(x+2)*5(5x-20)))+(-4xx/(2(x+2)*5(5x-20)))=0



We calculate terms in parentheses: +(5x5/(2(x+2)*5(5x-20))), so:

5x5/(2(x+2)*5(5x-20))

We multiply all the terms by the denominator


5x5

We add all the numbers together, and all the variables

5x^5

We do not support expression: x^5

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