1/2(x+10)=2(2x-7)

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Solution for 1/2(x+10)=2(2x-7) equation: 



1/2(x+10)=2(2x-7)

We move all terms to the left:

1/2(x+10)-(2(2x-7))=0



Domain of the equation: 2(x+10)!=0

x∈R



We multiply all the terms by the denominator


-((2(2x-7)))*2(x+10)+1=0



We calculate terms in parentheses: -((2(2x-7)))*2(x+10), so:

(2(2x-7)))*2(x+10





We calculate terms in parentheses: -((2(2x-7)))*2(x+10), so:

(2(2x-7)))*2(x+10





We calculate terms in parentheses: -((2(2x-7)))*2(x+10), so:

(2(2x-7)))*2(x+10





We calculate terms in parentheses: -((2(2x-7)))*2(x+10), so:

(2(2x-7)))*2(x+10





We calculate terms in parentheses: -((2(2x-7)))*2(x+10), so:

(2(2x-7)))*2(x+10





We calculate terms in parentheses: -((2(2x-7)))*2(x+10), so:

(2(2x-7)))*2(x+10





We calculate terms in parentheses: -((2(2x-7)))*2(x+10), so:

(2(2x-7)))*2(x+10





We calculate terms in parentheses: -((2(2x-7)))*2(x+10), so:

(2(2x-7)))*2(x+10





We calculate terms in parentheses: -((2(2x-7)))*2(x+10), so:

(2(2x-7)))*2(x+10





We calculate terms in parentheses: -((2(2x-7)))*2(x+10), so:

(2(2x-7)))*2(x+10





We calculate terms in parentheses: -((2(2x-7)))*2(x+10), so:

(2(2x-7)))*2(x+10





We calculate terms in parentheses: -((2(2x-7)))*2(x+10), so:

(2(2x-7)))*2(x+10





We calculate terms in parentheses: -((2(2x-7)))*2(x+10), so:

(2(2x-7)))*2(x+10





We calculate terms in parentheses: -((2(2x-7)))*2(x+10), so:

(2(2x-7)))*2(x+10





We calculate terms in parentheses: -((2(2x-7)))*2(x+10), so:

(2(2x-7)))*2(x+10





We calculate terms in parentheses: -((2(2x-7)))*2(x+10), so:

(2(2x-7)))*2(x+10





We calculate terms in parentheses: -((2(2x-7)))*2(x+10), so:

(2(2x-7)))*2(x+10





We calculate terms in parentheses: -((2(2x-7)))*2(x+10), so:

(2(2x-7)))*2(x+10





We calculate terms in parentheses: -((2(2x-7)))*2(x+10), so:

(2(2x-7)))*2(x+10





We calculate terms in parentheses: -((2(2x-7)))*2(x+10), so:

(2(2x-7)))*2(x+10





We calculate terms in parentheses: -((2(2x-7)))*2(x+10), so:

(2(2x-7)))*2(x+10





We calculate terms in parentheses: -((2(2x-7)))*2(x+10), so:

(2(2x-7)))*2(x+10





We calculate terms in parentheses: -((2(2x-7)))*2(x+10), so:

(2(2x-7)))*2(x+10





We calculate terms in parentheses: -((2(2x-7)))*2(x+10), so:

(2(2x-7)))*2(x+10





We calculate terms in parentheses: -((2(2x-7)))*2(x+10), so:

(2(2x-7)))*2(x+10





We calculate terms in parentheses: -((2(2x-7)))*2(x+10), so:

(2(2x-7)))*2(x+10





We calculate terms in parentheses: -((2(2x-7)))*2(x+10), so:

(2(2x-7)))*2(x+10





We calculate terms in parentheses: -((2(2x-7)))*2(x+10), so:

(2(2x-7)))*2(x+10





We calculate terms in parentheses: -((2(2x-7)))*2(x+10), so:

(2(2x-7)))*2(x+10





We calculate terms in parentheses: -((2(2x-7)))*2(x+10), so:

(2(2x-7)))*2(x+10





We calculate terms in parentheses: -((2(2x-7)))*2(x+10), so:

(2(2x-7)))*2(x+10





We calculate terms in parentheses: -((2(2x-7)))*2(x+10), so:

(2(2x-7)))*2(x+10





We calculate terms in parentheses: -((2(2x-7)))*2(x+10), so:

(2(2x-7)))*2(x+10





We calculate terms in parentheses: -((2(2x-7)))*2(x+10), so:

(2(2x-7)))*2(x+10





We calculate terms in parentheses: -((2(2x-7)))*2(x+10), so:

(2(2x-7)))*2(x+10





We calculate terms in parentheses: -((2(2x-7)))*2(x+10), so:

(2(2x-7)))*2(x+10





We calculate terms in parentheses: -((2(2x-7)))*2(x+10), so:

(2(2x-7)))*2(x+10





We calculate terms in parentheses: -((2(2x-7)))*2(x+10), so:

(2(2x-7)))*2(x+10





We calculate terms in parentheses: -((2(2x-7)))*2(x+10), so:

(2(2x-7)))*2(x+10





We calculate terms in parentheses: -((2(2x-7)))*2(x+10), so:

(2(2x-7)))*2(x+10





We calculate terms in parentheses: -((2(2x-7)))*2(x+10), so:

(2(2x-7)))*2(x+10





We calculate terms in parentheses: -((2(2x-7)))*2(x+10), so:

(2(2x-7)))*2(x+10





We calculate terms in parentheses: -((2(2x-7)))*2(x+10), so:

(2(2x-7)))*2(x+10





							

									
									
									
									
									
									

														
			

			
				

						
				
				
					
			
						
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