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1/2(x)+1+3/8(x)=7
We move all terms to the left:
1/2(x)+1+3/8(x)-(7)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 8x!=0We add all the numbers together, and all the variables
x!=0/8
x!=0
x∈R
1/2x+3/8x-6=0
We calculate fractions
8x/16x^2+6x/16x^2-6=0
We multiply all the terms by the denominator
8x+6x-6*16x^2=0
We add all the numbers together, and all the variables
14x-6*16x^2=0
Wy multiply elements
-96x^2+14x=0
a = -96; b = 14; c = 0;
Δ = b2-4ac
Δ = 142-4·(-96)·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-14}{2*-96}=\frac{-28}{-192} =7/48 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+14}{2*-96}=\frac{0}{-192} =0 $
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