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1/2(t+3)-4/9=1/9(3t+7)
We move all terms to the left:
1/2(t+3)-4/9-(1/9(3t+7))=0
Domain of the equation: 2(t+3)!=0
t∈R
Domain of the equation: 9(3t+7))!=0We calculate fractions
t∈R
(81t3/(2(t+3)*9(3t+7))*9)+(-2tt/(2(t+3)*9(3t+7))*9)+(-8tt/(2(t+3)*9(3t+7))*9)=0
We calculate terms in parentheses: +(81t3/(2(t+3)*9(3t+7))*9), so:
81t3/(2(t+3)*9(3t+7))*9
We multiply all the terms by the denominator
81t3
We add all the numbers together, and all the variables
81t^3
We do not support etpression: t^3
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