1/2(t+1)=1/3(t-6)

Solution for 1/2(t+1)=1/3(t-6) equation:

1/2(t+1)=1/3(t-6)

We move all terms to the left:

1/2(t+1)-(1/3(t-6))=0


Domain of the equation: 2(t+1)!=0

t∈R



Domain of the equation: 3(t-6))!=0

t∈R


We calculate fractions


(3tt/(2(t+1)*3(t-6)))+(-2tt/(2(t+1)*3(t-6)))=0


We calculate terms in parentheses: +(3tt/(2(t+1)*3(t-6))), so:

3tt/(2(t+1)*3(t-6))

We multiply all the terms by the denominator


3tt

Back to the equation:

+(3tt)



We calculate terms in parentheses: +(-2tt/(2(t+1)*3(t-6))), so:

-2tt/(2(t+1)*3(t-6))

We multiply all the terms by the denominator


-2tt

Back to the equation:

+(-2tt)


We get rid of parentheses

3tt-2tt=0