1/2(s-12)=1/4(s+6)

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Solution for 1/2(s-12)=1/4(s+6) equation: 



1/2(s-12)=1/4(s+6)

We move all terms to the left:

1/2(s-12)-(1/4(s+6))=0



Domain of the equation: 2(s-12)!=0

s∈R





Domain of the equation: 4(s+6))!=0

s∈R



We calculate fractions


(4ss/(2(s-12)*4(s+6)))+(-2ss/(2(s-12)*4(s+6)))=0



We calculate terms in parentheses: +(4ss/(2(s-12)*4(s+6))), so:

4ss/(2(s-12)*4(s+6))

We multiply all the terms by the denominator


4ss

Back to the equation:

+(4ss)





We calculate terms in parentheses: +(-2ss/(2(s-12)*4(s+6))), so:

-2ss/(2(s-12)*4(s+6))

We multiply all the terms by the denominator


-2ss

Back to the equation:

+(-2ss)



We get rid of parentheses

4ss-2ss=0

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