1/2(r-3)+2=1/3(r-9)

Solution for 1/2(r-3)+2=1/3(r-9) equation:

1/2(r-3)+2=1/3(r-9)

We move all terms to the left:

1/2(r-3)+2-(1/3(r-9))=0


Domain of the equation: 2(r-3)!=0

r∈R



Domain of the equation: 3(r-9))!=0

r∈R


We calculate fractions


(3rr/(2(r-3)*3(r-9)))+(-2rr/(2(r-3)*3(r-9)))+2=0


We calculate terms in parentheses: +(3rr/(2(r-3)*3(r-9))), so:

3rr/(2(r-3)*3(r-9))

We multiply all the terms by the denominator


3rr

Back to the equation:

+(3rr)



We calculate terms in parentheses: +(-2rr/(2(r-3)*3(r-9))), so:

-2rr/(2(r-3)*3(r-9))

We multiply all the terms by the denominator


-2rr

Back to the equation:

+(-2rr)


We get rid of parentheses

3rr-2rr+2=0

We move all terms containing r to the left, all other terms to the right

3rr-2rr=-2