1/2(q+6)=3/4(q-4)

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Solution for 1/2(q+6)=3/4(q-4) equation: 



1/2(q+6)=3/4(q-4)

We move all terms to the left:

1/2(q+6)-(3/4(q-4))=0



Domain of the equation: 2(q+6)!=0

q∈R





Domain of the equation: 4(q-4))!=0

q∈R



We calculate fractions


(4qq/(2(q+6)*4(q-4)))+(-6qq/(2(q+6)*4(q-4)))=0



We calculate terms in parentheses: +(4qq/(2(q+6)*4(q-4))), so:

4qq/(2(q+6)*4(q-4))

We multiply all the terms by the denominator


4qq

Back to the equation:

+(4qq)





We calculate terms in parentheses: +(-6qq/(2(q+6)*4(q-4))), so:

-6qq/(2(q+6)*4(q-4))

We multiply all the terms by the denominator


-6qq

Back to the equation:

+(-6qq)



We get rid of parentheses

4qq-6qq=0

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