1/2(b-2)=2/5(4b-3)

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Solution for 1/2(b-2)=2/5(4b-3) equation: 



1/2(b-2)=2/5(4b-3)

We move all terms to the left:

1/2(b-2)-(2/5(4b-3))=0



Domain of the equation: 2(b-2)!=0

b∈R





Domain of the equation: 5(4b-3))!=0

b∈R



We calculate fractions


(5b4/(2(b-2)*5(4b-3)))+(-4bb/(2(b-2)*5(4b-3)))=0



We calculate terms in parentheses: +(5b4/(2(b-2)*5(4b-3))), so:

5b4/(2(b-2)*5(4b-3))

We multiply all the terms by the denominator


5b4

We add all the numbers together, and all the variables

5b^4

We do not support ebpression: b^4

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