1/2(b+6)-1/3(3-b)=1/5(2b+7)

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Solution for 1/2(b+6)-1/3(3-b)=1/5(2b+7) equation:



1/2(b+6)-1/3(3-b)=1/5(2b+7)
We move all terms to the left:
1/2(b+6)-1/3(3-b)-(1/5(2b+7))=0
Domain of the equation: 2(b+6)!=0
b∈R
Domain of the equation: 3(3-b)!=0
b∈R
Domain of the equation: 5(2b+7))!=0
b∈R
We add all the numbers together, and all the variables
1/2(b+6)-1/3(-1b+3)-(1/5(2b+7))=0
We calculate fractions
(-10b^2b/(2(b+6)*3(-1b+3)*5(2b+7)))+(-6b^2b/(2(b+6)*3(-1b+3)*5(2b+7)))+(15b^2(-)/(2(b+6)*3(-1b+3)*5(2b+7)))=0
We calculate terms in parentheses: +(-10b^2b/(2(b+6)*3(-1b+3)*5(2b+7))), so:
-10b^2b/(2(b+6)*3(-1b+3)*5(2b+7))
We multiply all the terms by the denominator
-10b^2b
Back to the equation:
+(-10b^2b)
We calculate terms in parentheses: +(-6b^2b/(2(b+6)*3(-1b+3)*5(2b+7))), so:
-6b^2b/(2(b+6)*3(-1b+3)*5(2b+7))
We multiply all the terms by the denominator
-6b^2b
Back to the equation:
+(-6b^2b)
We calculate terms in parentheses: +(15b^2(-)/(2(b+6)*3(-1b+3)*5(2b+7))), so:
15b^2(-)/(2(b+6)*3(-1b+3)*5(2b+7))
We add all the numbers together, and all the variables
15b^20/(2(b+6)*3(-1b+3)*5(2b+7))
We multiply all the terms by the denominator
15b^20
We do not support ebpression: b^20

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