1/2(b+2)=5

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Solution for 1/2(b+2)=5 equation: 



1/2(b+2)=5

We move all terms to the left:

1/2(b+2)-(5)=0



Domain of the equation: 2(b+2)!=0

b∈R



We multiply all the terms by the denominator


-5*2(b+2)+1=0

Wy multiply elements

-10b(b+1=0

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