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1/2(a+4)-6=2/5(5-a)
We move all terms to the left:
1/2(a+4)-6-(2/5(5-a))=0
Domain of the equation: 2(a+4)!=0
a∈R
Domain of the equation: 5(5-a))!=0We add all the numbers together, and all the variables
a∈R
1/2(a+4)-(2/5(-1a+5))-6=0
We calculate fractions
(5a(-)/(2(a+4)*5(-1a+5)))+(-4aa/(2(a+4)*5(-1a+5)))-6=0
We calculate terms in parentheses: +(5a(-)/(2(a+4)*5(-1a+5))), so:
5a(-)/(2(a+4)*5(-1a+5))
We add all the numbers together, and all the variables
5a0/(2(a+4)*5(-1a+5))
We multiply all the terms by the denominator
5a0
We add all the numbers together, and all the variables
5a
Back to the equation:
+(5a)
We calculate terms in parentheses: +(-4aa/(2(a+4)*5(-1a+5))), so:We get rid of parentheses
-4aa/(2(a+4)*5(-1a+5))
We multiply all the terms by the denominator
-4aa
Back to the equation:
+(-4aa)
5a-4aa-6=0
We move all terms containing a to the left, all other terms to the right
5a-4aa=6
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