1/2(9x-9)=9/2x-t+9

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Solution for 1/2(9x-9)=9/2x-t+9 equation: 


x in (-oo:+oo)

(1/2)*(9*x-9) = (9/2)*x-t+9 // - (9/2)*x-t+9

(1/2)*(9*x-9)+t-((9/2)*x)-9 = 0

(1/2)*(9*x-9)+t+(-9/2)*x-9 = 0

1/2*(9*x-9)+t+(-9*x)/2-9 = 0

(1/2*2*(9*x-9))/2+(2*t)/2+(-9*x)/2+(-9*2)/2 = 0

1/2*2*(9*x-9)+2*t-9*x-9*2 = 0

2*t+9*x-9*x-18-9 = 0

2*t-18-9 = 0

2*t-27 = 0

(2*t-27)/2 = 0

(2*t-27)/2 = 0 // * 2

2*t-27 = 0

x belongs to the empty set

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