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1/2(8x-6)-x=5(x+2)-3
We move all terms to the left:
1/2(8x-6)-x-(5(x+2)-3)=0
Domain of the equation: 2(8x-6)!=0We add all the numbers together, and all the variables
x∈R
-1x+1/2(8x-6)-(5(x+2)-3)=0
We multiply all the terms by the denominator
-1x*2(8x-6)-((5(x+2)-3))*2(8x-6)+1=0
We calculate terms in parentheses: -((5(x+2)-3))*2(8x-6), so:Wy multiply elements
(5(x+2)-3))*2(8x-6
-2x^2(8-((5(x+2)-3))*2(8x-6)+1=0
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