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1/2(8x-4)=10+3x
We move all terms to the left:
1/2(8x-4)-(10+3x)=0
Domain of the equation: 2(8x-4)!=0We add all the numbers together, and all the variables
x∈R
1/2(8x-4)-(3x+10)=0
We get rid of parentheses
1/2(8x-4)-3x-10=0
We multiply all the terms by the denominator
-3x*2(8x-4)-10*2(8x-4)+1=0
Wy multiply elements
-6x^2(8-20x(8+1=0
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