1/2(8x-4)=1/3(12x+6)

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Solution for 1/2(8x-4)=1/3(12x+6) equation: 



1/2(8x-4)=1/3(12x+6)

We move all terms to the left:

1/2(8x-4)-(1/3(12x+6))=0



Domain of the equation: 2(8x-4)!=0

x∈R





Domain of the equation: 3(12x+6))!=0

x∈R



We calculate fractions


(3x1/(2(8x-4)*3(12x+6)))+(-2x8/(2(8x-4)*3(12x+6)))=0



We calculate terms in parentheses: +(3x1/(2(8x-4)*3(12x+6))), so:

3x1/(2(8x-4)*3(12x+6))

We multiply all the terms by the denominator


3x1

We add all the numbers together, and all the variables

3x

Back to the equation:

+(3x)





We calculate terms in parentheses: +(-2x8/(2(8x-4)*3(12x+6))), so:

-2x8/(2(8x-4)*3(12x+6))

We multiply all the terms by the denominator


-2x8

We add all the numbers together, and all the variables

-2x^8

We do not support expression: x^8

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