If it's not what You are looking for type in the equation solver your own equation and let us solve it.
1/2(8x-3)=x-1
We move all terms to the left:
1/2(8x-3)-(x-1)=0
Domain of the equation: 2(8x-3)!=0We get rid of parentheses
x∈R
1/2(8x-3)-x+1=0
We multiply all the terms by the denominator
-x*2(8x-3)+1*2(8x-3)+1=0
Wy multiply elements
-2x^2(8+2x(8+1=0
| 28=x÷3 | | 1/2x16=69 | | 2(3x-6)=3x/2 | | -16-x=3 | | 2/5(x+6)=12 | | 3x^2-6x=28 | | ((x-5)^2))(x+9)=0 | | 7/21=m/9 | | 3+5w=-27 | | 3(r+2)=-2r-4 | | 6/n=4/8 | | 5+4•x=6+2x | | 6/7(k+7/9)=3/13 | | 10m=10-5(m-2) | | 67(k+79)=3/1/3 | | -2x+2(2)=-2 | | -6x=18x-8 | | 2(27x-42)=6x^2 | | 4y+2+y=2 | | 84=-6(p-7) | | 67(k+79)=31/3 | | 6x-47=2×+24 | | 67(k+79)=3/13 | | 5/3x+1/3=112/3+7/3x | | -150=-16t^2+50t | | -2/7k=4/11 | | 5(2x+7)=-(1-4x) | | 2.4(10x+7)=148 | | 3n-6n=20 | | 13-4x+2=3x-7+2 | | 4y+2+y=2{2y+3} | | 5(61)(a^-2)+5a=0 |