1/2(8x-10)+x+8=-x+3(9-2x)-(x-2)

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Solution for 1/2(8x-10)+x+8=-x+3(9-2x)-(x-2) equation: 



1/2(8x-10)+x+8=-x+3(9-2x)-(x-2)

We move all terms to the left:

1/2(8x-10)+x+8-(-x+3(9-2x)-(x-2))=0



Domain of the equation: 2(8x-10)!=0

x∈R



We add all the numbers together, and all the variables

1/2(8x-10)+x-(-x+3(-2x+9)-(x-2))+8=0

We add all the numbers together, and all the variables

x+1/2(8x-10)-(-x+3(-2x+9)-(x-2))+8=0

We multiply all the terms by the denominator


x*2(8x-10)-((-x+3(-2x+9)-(x-2)))*2(8x-10)+8*2(8x-10)+1=0



We calculate terms in parentheses: -((-x+3(-2x+9)-(x-2)))*2(8x-10), so:

(-x+3(-2x+9)-(x-2)))*2(8x-10



Wy multiply elements

2x^2(8-((-x+3(-2x+9)-(x-2)))*2(8x-10)+16x(8+1=0

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