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1/2(8-2x)=3(2-x)
We move all terms to the left:
1/2(8-2x)-(3(2-x))=0
Domain of the equation: 2(8-2x)!=0We add all the numbers together, and all the variables
x∈R
1/2(-2x+8)-(3(-1x+2))=0
We multiply all the terms by the denominator
-((3(-1x+2)))*2(-2x+8)+1=0
We calculate terms in parentheses: -((3(-1x+2)))*2(-2x+8), so:We add all the numbers together, and all the variables
(3(-1x+2)))*2(-2x+8
We add all the numbers together, and all the variables
-2x+(3(-1x+2)))*2(+8
Back to the equation:
-(-2x+(3(-1x+2)))*2(+8)
-(-2x+(3(-1x+2)))*28+1=0
We move all terms containing x to the left, all other terms to the right
-(-2x+(3(-1x+2)))*28=-1
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