1/2(7x+48)=-(1/2x-3)+4(x+5)

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Solution for 1/2(7x+48)=-(1/2x-3)+4(x+5) equation: 



1/2(7x+48)=-(1/2x-3)+4(x+5)

We move all terms to the left:

1/2(7x+48)-(-(1/2x-3)+4(x+5))=0



Domain of the equation: 2(7x+48)!=0

x∈R





Domain of the equation: 2x-3)+4(x+5))!=0

x∈R



We calculate fractions


(2x-3)+4x/(28x^2+192x-3)+4x+(-(-(1*2(7x+48))/(28x^2+192x-3)+4x=0

We add all the numbers together, and all the variables

4x+(2x-3)+4x/(28x^2+192x-3)+(-(-(1*2(7x+48))/(28x^2+192x-3)+4x=0

We get rid of parentheses

4x+2x+4x/(28x^2+192x-3)+(-(-(1*2(7x+48))/(28x^2+192x-3)+4x-3=0

We calculate fractions

We do not support expression: x^3

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