1/2(6z-12)=30

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Solution for 1/2(6z-12)=30 equation: 



1/2(6z-12)=30

We move all terms to the left:

1/2(6z-12)-(30)=0



Domain of the equation: 2(6z-12)!=0

z∈R



We multiply all the terms by the denominator


-30*2(6z-12)+1=0

Wy multiply elements

-60z(6+1=0

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