1/2(6y+2y)(2+1)=20

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Solution for 1/2(6y+2y)(2+1)=20 equation: 


y in (-oo:+oo)

(1/2)*(1+2)*(6*y+2*y) = 20 // - 20

(1/2)*(1+2)*(6*y+2*y)-20 = 0

3/2*8*y-20 = 0

3/2*8*y-20 = 0

12*y-20 = 0

12*y-20 = 0

12*y-20 = 0 // + 20

12*y = 20 // : 12

y = 20/12

y = 5/3

y = 5/3

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