1/2(6y+14)+(4y-9)=12

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Solution for 1/2(6y+14)+(4y-9)=12 equation: 



1/2(6y+14)+(4y-9)=12

We move all terms to the left:

1/2(6y+14)+(4y-9)-(12)=0



Domain of the equation: 2(6y+14)!=0

y∈R



We get rid of parentheses

1/2(6y+14)+4y-9-12=0

We multiply all the terms by the denominator


4y*2(6y+14)-9*2(6y+14)-12*2(6y+14)+1=0

Wy multiply elements

8y^2(6-18y(6-24y(6+1=0

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