1/2(6x-8)=1/4(4x+40)

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Solution for 1/2(6x-8)=1/4(4x+40) equation: 



1/2(6x-8)=1/4(4x+40)

We move all terms to the left:

1/2(6x-8)-(1/4(4x+40))=0



Domain of the equation: 2(6x-8)!=0

x∈R





Domain of the equation: 4(4x+40))!=0

x∈R



We calculate fractions


(4x4/(2(6x-8)*4(4x+40)))+(-2x6/(2(6x-8)*4(4x+40)))=0



We calculate terms in parentheses: +(4x4/(2(6x-8)*4(4x+40))), so:

4x4/(2(6x-8)*4(4x+40))

We multiply all the terms by the denominator


4x4

We add all the numbers together, and all the variables

4x^4

We do not support expression: x^4

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