1/2(6x-8)=1/4(16x-12)

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Solution for 1/2(6x-8)=1/4(16x-12) equation: 



1/2(6x-8)=1/4(16x-12)

We move all terms to the left:

1/2(6x-8)-(1/4(16x-12))=0



Domain of the equation: 2(6x-8)!=0

x∈R





Domain of the equation: 4(16x-12))!=0

x∈R



We calculate fractions


(4x1/(2(6x-8)*4(16x-12)))+(-2x6/(2(6x-8)*4(16x-12)))=0



We calculate terms in parentheses: +(4x1/(2(6x-8)*4(16x-12))), so:

4x1/(2(6x-8)*4(16x-12))

We multiply all the terms by the denominator


4x1

We add all the numbers together, and all the variables

4x

Back to the equation:

+(4x)





We calculate terms in parentheses: +(-2x6/(2(6x-8)*4(16x-12))), so:

-2x6/(2(6x-8)*4(16x-12))

We multiply all the terms by the denominator


-2x6

We add all the numbers together, and all the variables

-2x^6

We do not support expression: x^6

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