1/2(6x-8)+3x+12=20

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Solution for 1/2(6x-8)+3x+12=20 equation: 



1/2(6x-8)+3x+12=20

We move all terms to the left:

1/2(6x-8)+3x+12-(20)=0



Domain of the equation: 2(6x-8)!=0

x∈R



We add all the numbers together, and all the variables

3x+1/2(6x-8)-8=0

We multiply all the terms by the denominator


3x*2(6x-8)-8*2(6x-8)+1=0

Wy multiply elements

6x^2(6-16x(6+1=0

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