1/2(6x-10)=1/3(12x+9)

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Solution for 1/2(6x-10)=1/3(12x+9) equation: 



1/2(6x-10)=1/3(12x+9)

We move all terms to the left:

1/2(6x-10)-(1/3(12x+9))=0



Domain of the equation: 2(6x-10)!=0

x∈R





Domain of the equation: 3(12x+9))!=0

x∈R



We calculate fractions


(3x1/(2(6x-10)*3(12x+9)))+(-2x6/(2(6x-10)*3(12x+9)))=0



We calculate terms in parentheses: +(3x1/(2(6x-10)*3(12x+9))), so:

3x1/(2(6x-10)*3(12x+9))

We multiply all the terms by the denominator


3x1

We add all the numbers together, and all the variables

3x

Back to the equation:

+(3x)





We calculate terms in parentheses: +(-2x6/(2(6x-10)*3(12x+9))), so:

-2x6/(2(6x-10)*3(12x+9))

We multiply all the terms by the denominator


-2x6

We add all the numbers together, and all the variables

-2x^6

We do not support expression: x^6

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