1/2(6x+14)=x+1+2(x+3)

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Solution for 1/2(6x+14)=x+1+2(x+3) equation: 


x in (-oo:+oo)

(1/2)*(6*x+14) = 2*(x+3)+x+1 // - 2*(x+3)+x+1

(1/2)*(6*x+14)-(2*(x+3))-x-1 = 0

(1/2)*(6*x+14)-2*(x+3)-x-1 = 0

1/2*(6*x+14)-2*(x+3)-x-1 = 0

1/2*(6*x+14)-2*(x+3)-x-1 = 0

x-x-1+1 = 0

1-1 = 0

0 = 0

0 = 0

x belongs to the empty set

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