1/2(6x+10)+x=9x+5(1-x)

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Solution for 1/2(6x+10)+x=9x+5(1-x) equation: 



1/2(6x+10)+x=9x+5(1-x)

We move all terms to the left:

1/2(6x+10)+x-(9x+5(1-x))=0



Domain of the equation: 2(6x+10)!=0

x∈R



We add all the numbers together, and all the variables

1/2(6x+10)+x-(9x+5(-1x+1))=0

We add all the numbers together, and all the variables

x+1/2(6x+10)-(9x+5(-1x+1))=0

We multiply all the terms by the denominator


x*2(6x+10)-((9x+5(-1x+1)))*2(6x+10)+1=0



We calculate terms in parentheses: -((9x+5(-1x+1)))*2(6x+10), so:

(9x+5(-1x+1)))*2(6x+10



Wy multiply elements

2x^2(6-((9x+5(-1x+1)))*2(6x+10)+1=0

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