1/2(6-12)=3/4(4-8n)

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Solution for 1/2(6-12)=3/4(4-8n) equation: 



1/2(6-12)=3/4(4-8n)

We move all terms to the left:

1/2(6-12)-(3/4(4-8n))=0



Domain of the equation: 4(4-8n))!=0

n∈R



We add all the numbers together, and all the variables

-(3/4(-8n+4))+1/2(-6)=0

We calculate fractions


()/(4(-8n+4))*2()+(4n(-)/(4(-8n+4))*2()=0



We calculate terms in parentheses: +()/(4(-8n+4))*2(), so:

)/(4(-8n+4))*2(

We multiply all the terms by the denominator


)

We add all the numbers together, and all the variables



Back to the equation:

+()





We calculate terms in parentheses: +(4n(-)/(4(-8n+4))*2(), so:

4n(-)/(4(-8n+4))*2(

We add all the numbers together, and all the variables

4n0/(4(-8n+4))*2(

We multiply all the terms by the denominator


4n0

We add all the numbers together, and all the variables

4n

Back to the equation:

+(4n)



We add all the numbers together, and all the variables

4n=0

n=0/4

n=0

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