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1/2(5x-8)=2/3(6-4x)
We move all terms to the left:
1/2(5x-8)-(2/3(6-4x))=0
Domain of the equation: 2(5x-8)!=0
x∈R
Domain of the equation: 3(6-4x))!=0We add all the numbers together, and all the variables
x∈R
1/2(5x-8)-(2/3(-4x+6))=0
We calculate fractions
(3x(-)/(2(5x-8)*3(-4x+6)))+(-4x5/(2(5x-8)*3(-4x+6)))=0
We calculate terms in parentheses: +(3x(-)/(2(5x-8)*3(-4x+6))), so:
3x(-)/(2(5x-8)*3(-4x+6))
We add all the numbers together, and all the variables
3x0/(2(5x-8)*3(-4x+6))
We multiply all the terms by the denominator
3x0
We add all the numbers together, and all the variables
3x
Back to the equation:
+(3x)
We calculate terms in parentheses: +(-4x5/(2(5x-8)*3(-4x+6))), so:
-4x5/(2(5x-8)*3(-4x+6))
We multiply all the terms by the denominator
-4x5
We add all the numbers together, and all the variables
-4x^5
We do not support expression: x^5
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