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(1/2)*(5*x-6) = 3*x-(0.5*x) // - 3*x-(0.5*x)
(1/2)*(5*x-6)-(3*x)+0.5*x = 0
(1/2)*(5*x-6)-3*x+0.5*x = 0
1/2*(5*x-6)-3*x+0.5*x = 0
1/2*(5*x-6)-3*x+0.5*x = 0
0.5*x-1/2*x-3 = 0
-3 = 0
-3 = 0
-3 = 0
x belongs to the empty set
x belongs to the empty set
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