1/2(4y-8)+2y=12

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Solution for 1/2(4y-8)+2y=12 equation: 



1/2(4y-8)+2y=12

We move all terms to the left:

1/2(4y-8)+2y-(12)=0



Domain of the equation: 2(4y-8)!=0

y∈R



We add all the numbers together, and all the variables

2y+1/2(4y-8)-12=0

We multiply all the terms by the denominator


2y*2(4y-8)-12*2(4y-8)+1=0

Wy multiply elements

4y^2(4-24y(4+1=0

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