1/2(4y+12)=-1/4(8y-12)

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Solution for 1/2(4y+12)=-1/4(8y-12) equation:



1/2(4y+12)=-1/4(8y-12)
We move all terms to the left:
1/2(4y+12)-(-1/4(8y-12))=0
Domain of the equation: 2(4y+12)!=0
y∈R
Domain of the equation: 4(8y-12))!=0
y∈R
We calculate fractions
(4y8/(2(4y+12)*4(8y-12)))+(-(-2y4)/(2(4y+12)*4(8y-12)))=0
We calculate terms in parentheses: +(4y8/(2(4y+12)*4(8y-12))), so:
4y8/(2(4y+12)*4(8y-12))
We multiply all the terms by the denominator
4y8
We add all the numbers together, and all the variables
4y^8
We do not support eypression: y^8

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