If it's not what You are looking for type in the equation solver your own equation and let us solve it.
1/2(4y+12)+3=2y+9
We move all terms to the left:
1/2(4y+12)+3-(2y+9)=0
Domain of the equation: 2(4y+12)!=0We get rid of parentheses
y∈R
1/2(4y+12)-2y-9+3=0
We multiply all the terms by the denominator
-2y*2(4y+12)-9*2(4y+12)+3*2(4y+12)+1=0
Wy multiply elements
-4y^2(4-18y(4+6y(4+1=0
| |2x|+1=9 | | 3x2+9=-27 | | 6+2.5x=41 | | -2+20-19c=-c+18 | | 3x−2=−4x−65 | | 4(z-1)^2=15 | | n(n+2)=116 | | -2(x-2)=40 | | 7b-9=6b | | 5x=9-29 | | 4x-12=2(2x+5) | | 5)3x2+9=-27 | | F(4)=12x | | 3.5/6=x/1.2 | | 1/313(d+9)=-12 | | |7-4w|=13 | | -8x=4(x-8) | | 57+y=1.6 | | (x+3)+80=6x+23 | | 7x-6(7x5)=57 | | 6+2.5=0.5x-8 | | 5(3x+4)-7x=6x-8+2x+20 | | 5k-7=6k | | 7(k-91)=49 | | 4-8v=-2(4v-2) | | 4(1+2m)=5m-14 | | 12x+10+4x=16x-10 | | 13(6q–2)=4q–73q–12 | | 4(z-1)=15 | | (5x-2x+4)=(2x+4x-3 | | 25+j=−3(j−7) | | 3x+9+2x-4=35 |