1/2(4x-5)=1/2(-6x+5)

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Solution for 1/2(4x-5)=1/2(-6x+5) equation: 



1/2(4x-5)=1/2(-6x+5)

We move all terms to the left:

1/2(4x-5)-(1/2(-6x+5))=0



Domain of the equation: 2(4x-5)!=0

x∈R





Domain of the equation: 2(-6x+5))!=0

x∈R



We calculate fractions


(2x(-)/(2(4x-5)*2(-6x+5)))+(-2x4/(2(4x-5)*2(-6x+5)))=0



We calculate terms in parentheses: +(2x(-)/(2(4x-5)*2(-6x+5))), so:

2x(-)/(2(4x-5)*2(-6x+5))

We add all the numbers together, and all the variables

2x0/(2(4x-5)*2(-6x+5))

We multiply all the terms by the denominator


2x0

We add all the numbers together, and all the variables

2x

Back to the equation:

+(2x)





We calculate terms in parentheses: +(-2x4/(2(4x-5)*2(-6x+5))), so:

-2x4/(2(4x-5)*2(-6x+5))

We multiply all the terms by the denominator


-2x4

We add all the numbers together, and all the variables

-2x^4

We do not support expression: x^4

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