1/2(4x-2)=3/10(20x-10)

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Solution for 1/2(4x-2)=3/10(20x-10) equation: 



1/2(4x-2)=3/10(20x-10)

We move all terms to the left:

1/2(4x-2)-(3/10(20x-10))=0



Domain of the equation: 2(4x-2)!=0

x∈R





Domain of the equation: 10(20x-10))!=0

x∈R



We calculate fractions


(10x2/(2(4x-2)*10(20x-10)))+(-6x4/(2(4x-2)*10(20x-10)))=0



We calculate terms in parentheses: +(10x2/(2(4x-2)*10(20x-10))), so:

10x2/(2(4x-2)*10(20x-10))

We multiply all the terms by the denominator


10x2

We add all the numbers together, and all the variables

10x^2

Back to the equation:

+(10x^2)





We calculate terms in parentheses: +(-6x4/(2(4x-2)*10(20x-10))), so:

-6x4/(2(4x-2)*10(20x-10))

We multiply all the terms by the denominator


-6x4

We add all the numbers together, and all the variables

-6x^4

We do not support expression: x^4

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