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1/2(4x-10)=1/3(9x+12)
We move all terms to the left:
1/2(4x-10)-(1/3(9x+12))=0
Domain of the equation: 2(4x-10)!=0
x∈R
Domain of the equation: 3(9x+12))!=0We calculate fractions
x∈R
(3x9/(2(4x-10)*3(9x+12)))+(-2x4/(2(4x-10)*3(9x+12)))=0
We calculate terms in parentheses: +(3x9/(2(4x-10)*3(9x+12))), so:
3x9/(2(4x-10)*3(9x+12))
We multiply all the terms by the denominator
3x9
We add all the numbers together, and all the variables
3x^9
We do not support expression: x^9
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