1/2(4x+8)=1/5(20x-10)

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Solution for 1/2(4x+8)=1/5(20x-10) equation: 



1/2(4x+8)=1/5(20x-10)

We move all terms to the left:

1/2(4x+8)-(1/5(20x-10))=0



Domain of the equation: 2(4x+8)!=0

x∈R





Domain of the equation: 5(20x-10))!=0

x∈R



We calculate fractions


(5x2/(2(4x+8)*5(20x-10)))+(-2x4/(2(4x+8)*5(20x-10)))=0



We calculate terms in parentheses: +(5x2/(2(4x+8)*5(20x-10))), so:

5x2/(2(4x+8)*5(20x-10))

We multiply all the terms by the denominator


5x2

We add all the numbers together, and all the variables

5x^2

Back to the equation:

+(5x^2)





We calculate terms in parentheses: +(-2x4/(2(4x+8)*5(20x-10))), so:

-2x4/(2(4x+8)*5(20x-10))

We multiply all the terms by the denominator


-2x4

We add all the numbers together, and all the variables

-2x^4

We do not support expression: x^4

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