1/2(4x+8)=1/3(12x+6)

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Solution for 1/2(4x+8)=1/3(12x+6) equation:



1/2(4x+8)=1/3(12x+6)
We move all terms to the left:
1/2(4x+8)-(1/3(12x+6))=0
Domain of the equation: 2(4x+8)!=0
x∈R
Domain of the equation: 3(12x+6))!=0
x∈R
We calculate fractions
(3x1/(2(4x+8)*3(12x+6)))+(-2x4/(2(4x+8)*3(12x+6)))=0
We calculate terms in parentheses: +(3x1/(2(4x+8)*3(12x+6))), so:
3x1/(2(4x+8)*3(12x+6))
We multiply all the terms by the denominator
3x1
We add all the numbers together, and all the variables
3x
Back to the equation:
+(3x)
We calculate terms in parentheses: +(-2x4/(2(4x+8)*3(12x+6))), so:
-2x4/(2(4x+8)*3(12x+6))
We multiply all the terms by the denominator
-2x4
We add all the numbers together, and all the variables
-2x^4
We do not support expression: x^4

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