1/2(4x+20)=1/2(2x+6)

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Solution for 1/2(4x+20)=1/2(2x+6) equation: 



1/2(4x+20)=1/2(2x+6)

We move all terms to the left:

1/2(4x+20)-(1/2(2x+6))=0



Domain of the equation: 2(4x+20)!=0

x∈R





Domain of the equation: 2(2x+6))!=0

x∈R



We calculate fractions


(2x2/(2(4x+20)*2(2x+6)))+(-2x4/(2(4x+20)*2(2x+6)))=0



We calculate terms in parentheses: +(2x2/(2(4x+20)*2(2x+6))), so:

2x2/(2(4x+20)*2(2x+6))

We multiply all the terms by the denominator


2x2

We add all the numbers together, and all the variables

2x^2

Back to the equation:

+(2x^2)





We calculate terms in parentheses: +(-2x4/(2(4x+20)*2(2x+6))), so:

-2x4/(2(4x+20)*2(2x+6))

We multiply all the terms by the denominator


-2x4

We add all the numbers together, and all the variables

-2x^4

We do not support expression: x^4

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