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1/2(4x+12)-15=-4/5(15x-10)
We move all terms to the left:
1/2(4x+12)-15-(-4/5(15x-10))=0
Domain of the equation: 2(4x+12)!=0
x∈R
Domain of the equation: 5(15x-10))!=0We calculate fractions
x∈R
(5x1/(2(4x+12)*5(15x-10)))+(-(-8x4)/(2(4x+12)*5(15x-10)))-15=0
We calculate terms in parentheses: +(5x1/(2(4x+12)*5(15x-10))), so:
5x1/(2(4x+12)*5(15x-10))
We multiply all the terms by the denominator
5x1
We add all the numbers together, and all the variables
5x
Back to the equation:
+(5x)
We calculate terms in parentheses: +(-(-8x4)/(2(4x+12)*5(15x-10))), so:
-(-8x4)/(2(4x+12)*5(15x-10))
We add all the numbers together, and all the variables
-(-8x^4)/(2(4x+12)*5(15x-10))
We multiply all the terms by the denominator
-(-8x^4)
We do not support expression: x^4
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