1/2(4g-16)+40=72

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Solution for 1/2(4g-16)+40=72 equation: 



1/2(4g-16)+40=72

We move all terms to the left:

1/2(4g-16)+40-(72)=0



Domain of the equation: 2(4g-16)!=0

g∈R



We add all the numbers together, and all the variables

1/2(4g-16)-32=0

We multiply all the terms by the denominator


-32*2(4g-16)+1=0

Wy multiply elements

-64g(4+1=0

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