1/2(4g+18)=1/6(6-12g)

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Solution for 1/2(4g+18)=1/6(6-12g) equation: 



1/2(4g+18)=1/6(6-12g)

We move all terms to the left:

1/2(4g+18)-(1/6(6-12g))=0



Domain of the equation: 2(4g+18)!=0

g∈R





Domain of the equation: 6(6-12g))!=0

g∈R



We add all the numbers together, and all the variables

1/2(4g+18)-(1/6(-12g+6))=0

We calculate fractions


(6g(-)/(2(4g+18)*6(-12g+6)))+(-2g4/(2(4g+18)*6(-12g+6)))=0



We calculate terms in parentheses: +(6g(-)/(2(4g+18)*6(-12g+6))), so:

6g(-)/(2(4g+18)*6(-12g+6))

We add all the numbers together, and all the variables

6g0/(2(4g+18)*6(-12g+6))

We multiply all the terms by the denominator


6g0

We add all the numbers together, and all the variables

6g

Back to the equation:

+(6g)





We calculate terms in parentheses: +(-2g4/(2(4g+18)*6(-12g+6))), so:

-2g4/(2(4g+18)*6(-12g+6))

We multiply all the terms by the denominator


-2g4

We add all the numbers together, and all the variables

-2g^4

We do not support egpression: g^4

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