1/2(4c+33)=1/4(2c+9)

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Solution for 1/2(4c+33)=1/4(2c+9) equation: 



1/2(4c+33)=1/4(2c+9)

We move all terms to the left:

1/2(4c+33)-(1/4(2c+9))=0



Domain of the equation: 2(4c+33)!=0

c∈R





Domain of the equation: 4(2c+9))!=0

c∈R



We calculate fractions


(4c2/(2(4c+33)*4(2c+9)))+(-2c4/(2(4c+33)*4(2c+9)))=0



We calculate terms in parentheses: +(4c2/(2(4c+33)*4(2c+9))), so:

4c2/(2(4c+33)*4(2c+9))

We multiply all the terms by the denominator


4c2

We add all the numbers together, and all the variables

4c^2

Back to the equation:

+(4c^2)





We calculate terms in parentheses: +(-2c4/(2(4c+33)*4(2c+9))), so:

-2c4/(2(4c+33)*4(2c+9))

We multiply all the terms by the denominator


-2c4

We add all the numbers together, and all the variables

-2c^4

We do not support ecpression: c^4

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