1/2(4-6x)+12(x-7)=8

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Solution for 1/2(4-6x)+12(x-7)=8 equation: 



1/2(4-6x)+12(x-7)=8

We move all terms to the left:

1/2(4-6x)+12(x-7)-(8)=0



Domain of the equation: 2(4-6x)!=0

x∈R



We add all the numbers together, and all the variables

1/2(-6x+4)+12(x-7)-8=0

We multiply parentheses

1/2(-6x+4)+12x-84-8=0

We multiply all the terms by the denominator


12x*2(-6x+4)-84*2(-6x+4)-8*2(-6x+4)+1=0

Wy multiply elements

24x^2(--168x(--16x(-+1=0

We use the square of the difference formula

24x^2(+168x(+16x(-1=0

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