1/2(4-6)+6x=7(x+1)

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Solution for 1/2(4-6)+6x=7(x+1) equation: 



1/2(4-6)+6x=7(x+1)

We move all terms to the left:

1/2(4-6)+6x-(7(x+1))=0

We add all the numbers together, and all the variables

6x-(7(x+1))+1/2(-2)=0

We multiply all the terms by the denominator


6x*2(-2)-((7(x+1)))*2(-2)+1=0



We calculate terms in parentheses: -((7(x+1)))*2(-2), so:

(7(x+1)))*2(-2



Wy multiply elements

12x^2(--((7(x+1)))*2(-2)+1=0

We use the square of the difference formula

12x^2(+((7(x+1)))*2(-2)+1=0

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