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1/2(3x-5)=2/3(x-1)
We move all terms to the left:
1/2(3x-5)-(2/3(x-1))=0
Domain of the equation: 2(3x-5)!=0
x∈R
Domain of the equation: 3(x-1))!=0We calculate fractions
x∈R
(3xx/(2(3x-5)*3(x-1)))+(-4x3/(2(3x-5)*3(x-1)))=0
We calculate terms in parentheses: +(3xx/(2(3x-5)*3(x-1))), so:
3xx/(2(3x-5)*3(x-1))
We multiply all the terms by the denominator
3xx
Back to the equation:
+(3xx)
We calculate terms in parentheses: +(-4x3/(2(3x-5)*3(x-1))), so:
-4x3/(2(3x-5)*3(x-1))
We multiply all the terms by the denominator
-4x3
We add all the numbers together, and all the variables
-4x^3
We do not support expression: x^3
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