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1/2(3x-5)=1/4(x+8)
We move all terms to the left:
1/2(3x-5)-(1/4(x+8))=0
Domain of the equation: 2(3x-5)!=0
x∈R
Domain of the equation: 4(x+8))!=0We calculate fractions
x∈R
(4xx/(2(3x-5)*4(x+8)))+(-2x3/(2(3x-5)*4(x+8)))=0
We calculate terms in parentheses: +(4xx/(2(3x-5)*4(x+8))), so:
4xx/(2(3x-5)*4(x+8))
We multiply all the terms by the denominator
4xx
Back to the equation:
+(4xx)
We calculate terms in parentheses: +(-2x3/(2(3x-5)*4(x+8))), so:
-2x3/(2(3x-5)*4(x+8))
We multiply all the terms by the denominator
-2x3
We add all the numbers together, and all the variables
-2x^3
We do not support expression: x^3
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